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X^2+9X+5=-5
We move all terms to the left:
X^2+9X+5-(-5)=0
We add all the numbers together, and all the variables
X^2+9X+10=0
a = 1; b = 9; c = +10;
Δ = b2-4ac
Δ = 92-4·1·10
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{41}}{2*1}=\frac{-9-\sqrt{41}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{41}}{2*1}=\frac{-9+\sqrt{41}}{2} $
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